If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is
Given,
In parallelogram ABCD
∠A+∠B = 180° [adjacent angles of parallelogram are supplementary]

∠ A = ![]()
So, ![]()
= ![]()
= ![]()
∠A = ![]()
Thus smallest angle of parallelogram is 72°
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