Q7 of 95 Page 15

If ABCD is a rectangle with ∠BAC=32°, find the measure of ∠DBC.

Given,


ABCD is a rectangle



∠BAC = 32°


∵ we know that diagonals of a rectangle bisects each other


Hence , AO = BO


And, ∠DBA = ∠BAC = 32° (angles infront of same sides)


∵ ∠DBC+∠DBA = 90°


∴ ∠DBC = 90° - 32° = 58°


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