Q16 of 95 Page 15

In a parallelogram ABCD, if ∠DAB=75° and ∠DBC=60°, then ∠BDC=

Given ,


In parallelogram ABCD,


∠DAB = 75°



∠DBC = 60°


∵ ∠DAB= ∠BCD [opposite angles of parallelogram]


∠BCD = 75°


Now in ∆BDC


= ∠DBC+∠BDC+∠BCD = 180°


= 60°+∠BDC+75° = 180°


=∠BDC = 180° - 135°


=∠BDC = 45°.

More from this chapter

All 95 →
14

The figure formed by joining the mid-points of the adjacent sides of a parallelogram is a

 15

If one side of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is

 17

ABCD is a parallelogram and E and F are the centroids of triangles ABD and BCD respectively, then EF=

 18

ABCD is a parallelogram M is the mid-point of BD and BM bisects ∠B. Then, ∠AMB=