Q4 of 113 Page 65

The zeros of the polynomial x2 ‒ √2 x – 12 are

We have, f(x) = x2 ‒ x – 12


Now, put f(x) = 0


x2 ‒ x – 12 = 0


x(x ‒ 3√2) + 2√2 x – 3√2)=0


(x ‒ 3√2) + (x + 2√2) = 0


Thus, x= 3√2 , -2√2


Hence option B is correct.

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