Q7 of 113 Page 65

The zeros of the polynomial are


f(x) = 21x2 – 11x – 2 =0


Now, put f(x) = 0


21x2 – 11x – 2 =0


21x2 – 14x + 3x – 2 =0


7x(3x – 2) + 1 (3x – 2) = 0


(3x – 2) (7x + 1) = 0



Hence, option A is correct.

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