Q2 of 113 Page 71

If α, β, γ are the zeros of the polynomial x3 – 6x2 – x + 30 then the value of (αβ + βγ + γ α) is

We have,

p (x) = x3 – 6x2 – x + 3


Now we will compare the given polynomial with: x3 – () x2 + () x –


By comparing we get:


() = - 1

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