If –2 and 3 are the zeros of the quadratic polynomial x2 + (a + 1) x + b then

Question

Philoid · Accepted Answer

It is given in the question that, -2 and 3 are the zeros of x² + (a + 1) x + b

∴ (- 2)² + (a + 1) × (- 2) + b = 0

4 – 2a – 2 + b = 0

b – 2a = - 2 (i)

Also, we have

3² + (a + 1) × 3 + b = 0

9 + 3a + 3 + b = 0

b + 3a = - 12 (ii)

Now, by subtracting the equation (i) from (ii) we get:

a = - 2

Also, b = - 2 – 4 = - 6

If –2 and 3 are the zeros of the quadratic polynomial x² + (a + 1) x + b then