Q25 of 113 Page 65

If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is –1 then the product of the other two zeros is

It is given in the question that,


- 1 is the zero of the given polynomial x3 + ax2 + bx + c


∴ (- 1)3 + a × (- 1)2 + b × (- 1) + c = 0


a – b + c + 1 = 0


c = 1 – a + b


Also, the product of all zeros is:


× (- 1) = - c


= c


= 1 – a + b


Hence, option C is correct

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