Write the first three terms of the following sequences whose nth terms are given by
(i)
(ii) cn = (–1)n3n+2 (iii) 
(i) Here, an = ![]()
For n = 1, a1 =
=
= ![]()
For n = 2, a2 =
=
=
= 0
For n = 3, a3 =
=
=
= 1
Hence, the first three terms of the sequence are
, 0 and 1.
(ii) Here, cn = (-1)n 3n + 2
For n = 1, c1 = (-1)1 31 + 2 = (-1) 33 = (-1) (27) = -27
For n = 2, c2 = (-1)2 32 + 2 = (1) 34 = (1) (81) = 81
For n = 3, c3 = (-1)3 33 + 2 = (-1) 35 = (-1) (243) = -243
Hence, the first three terms of the sequence are -27, 81 and -243.
(iii) Here, zn = ![]()
For n = 1, z1 =
=
= ![]()
For n = 2, z2 =
=
=
= 2
For n = 3, z3 =
=
= ![]()
Hence, the first three terms of the sequence are
, 2 and
.
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