Find the sum of the following series.
2 + 4 + 6 + … + 100
Given the series S = 2 + 4 + 6 + … + 100,
We see that there is a common term 2 in all the numbers in the series. Taking 2 common, we have
S = 2(1 + 2 + 3 + .. + 50)
Let 1 + 2 + 3 + .. + 50 be S1, with n = 50
S = 2S1
To find S1 -
Formula for sum of first n numbers is
S1 = ![]()
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25x51
= 1275
S = 2S1
= 2 × 1275 = 2550
S = 2550
The sum S = 2 + 4 + 6 + … + 100 = 2550
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