Find the first five terms of the sequence given by a1 = 2, a2 = 3 + a1and an = 2an-1 + 5 for n>2.
Given that a1 = 2, a2 = 3 + a1 and an = 2an-1 + 5 for n > 2.
Now, a1 = 2
⇒ a2 = 3 + a1 = 3 + 2 = 5
⇒ a3 = 2a2 + 5 = 2(5) + 5 = 10 + 5 = 15
⇒ a4 = 2a3 + 5 = 2(15) + 5 = 30 + 5 = 35
⇒ a5 = 2a4 + 5 = 2(35) + 5 = 70 + 5 = 75
∴ The required terms of sequence are 2, 5, 15, 35 and 75.
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