Here, first term, a = 24
We know that common difference, d = a1 – a.

We know that nth term of A.P. , tn = a + (n – 1) d.
To find the nth term, here tn = 3
⇒ 3 = 24 + (n – 1) (-3/4)
⇒ 3 – 24 = (n – 1) (-3/4)
⇒ -21 = (n – 1) (-3/4)
⇒ -21 ×
= n – 1
⇒ 28 = n – 1
⇒ n = 28 + 1 = 29
∴ t29 of the given A.P. is 3.
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