(i) In the A.P.
First term = 38
Last term = 2
Common difference = 35–38 = –3
Nth term = a + (n–1) d
⇒ 2 = 38 + (n–1)(–3)
⇒ –36 = (n–1)(–3)
⇒ 12 = (n–1)
⇒ n = 13
Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = 260
(ii) In the A.P.
First term = 6
No. of terms = 25
Common difference = 21/4 – 6 = –3/4
Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = –75
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