Find the sum of the following series.
162 + 172 + 18 + … + 252
Given the the series S = 162 + 172 + 18 + … + 252
Let S1 = 12 + 22 + 32 + … + 252 with n = 25
Let S2 = 12 + 22 + 32 + .. + 152 with n = 15
Required sum S = S1-S2
To find the sum S1 -
Formula to find the sum of first n squares of natural numbers is
S = ![]()
S1 = ![]()
= ![]()
S1 = 5525
To find the sum S2 -
Formula to find the sum of first n squares of natural numbers is
S = ![]()
S2 = ![]()
S2 = ![]()
S2 = 1240
Required sum S = S1-S2
S = 5525-1240 = 4285
The sum S = 162 + 172 + 18 + … + 252 = 4285
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