The sum of three terms of a geometric sequence is
and their product is 1. Find the common ratio and the terms.
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⇒ second term = a and third term = ar.
(where, r is common ratio)
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……..(1)
Also, their product is 1.
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⇒ a3 = 1
⇒ a = 1
Substituting a = 1 in equation (1)
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⇒ 10 + 10r + 10r2 = 39r
⇒ 10r2-29r + 10 = 0
⇒ 10r2-25r-4r + 10 = 0
⇒ 5r(2r-5)-2(2r-5)
⇒ (5r-2) (2r-5) = 0
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Now, G.P will be-
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