Find the sum of all natural numbers between 300 and 500 which are divisible by 11.
Series of all natural numbers divisible by 11 between 300and 500 is:
308, 319,………………………………495
In the A.P.
First term = 308
Last term = 495
Common difference = 11
Nth term = a + (n–1) d
⇒ 495 = 308 + (n–1)11
⇒ 187 = (n–1)11
⇒ 17 = (n–1)
⇒ n = 18
Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = 7227
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