A geometric series consists of even number of terms. The sum of all terms is 3 times the sum of odd terms. Find the common ratio.
Ans. r = 2
In the G.P.,
Let First term = a,
Common ratio = r
Series: a, ar, ar2,…….arn–1
Sum of all terms = ![]()
For odd terms,
a, ar2,………arn–2
First term = a
Common ratio = r2
Number of terms = n/2
Sum of odd terms = 
⇒ Sum of odd terms = ![]()
Now,
Sum of all terms = 3× Sum of odd terms
⇒
= 3 × ![]()
⇒ (1–r2) = 3(1–r)
⇒ r2–3r + 2 = 0
⇒ r2–2r–r + 2 = 0
⇒ r(r–2)–1(r–2) = 0
⇒ (r–1) (r–2) = 0
r = 1 or r = 2
But r = 1 is not possible, So r = 2.
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