If a, b, c, d are in a G.P., then prove that a + b, b + c, c + d, are also in G.P.
Proof: ∵ a, b, c, d are in G.P
⇒ a = a, b = ar ,c = ar2,d = ar3.
To prove: a + b, b + c, c + d, are also in G.P, if-
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⇒ (a + b) (c + d) = (b + c)2
Now, we need to prove : (a + b) (c + d) = (b + c)2
L.H.S. = (a + ar)(ar2 + ar3)
= a(1 + r) ar2 (1 + r)
= a2r2 (1 + r)2
R.H.S. = (ar + ar2)2
= (ar(1 + r))2
= a2r2 (1 + r)2
⇒ L.H.S = R.H.S
Hence, proved that-
(a + b) (c + d) = (b + c)2
⇒ a + b, b + c, c + d, are also in G.P
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