A sum of ₹1000 is deposited every year at 8% simple interest. Calculate the interest at the end of each year. Do these interest amounts form an A.P.? If so, find the total interest at the end of 30 years.
Simple interest = P* R * T /100
P = ₹1000
R = 8
T = 1
Simple interest = 1000*8*1/100 = 80
Interest at the end of first year = ₹80
For second year,
P = 1000 + 1000 = 2000
R = 8
T = 1
Simple interest = 2000*8*1/100 = 160
Interest at the end of second year = ₹160
Similarly, for third year, P = 1000 + 1000 + 1000 = 3000
SI = 240.
Yes the simple interests form an A.P.
a = 80
d = 160–80 = 80
n = 30
Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = ![]()
⇒ Sum of terms = 37200
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.