If a, b, c, l, m are in A.P, then the value of a - 4b + 6c - 4l + m is
If a, b, c, l, m are in A.P, then
b-a = c-b = l-c = m-l.
a-4b + 6c-4l + m becomes
a-b-b-b-b + c + c + c + c + c + c-l-l-l-l + m
Grouping the terms
We have
a + 4(c-b)-2(l-c)-2l + m
a + 2(c-b)-2(l-c) + 2(c-b)-2l + m
Since c-b = l-c,
a + 2(c-b)-2l + m
a + 2c-2b-2l + m
-(b-a) + (c-b)-(l-c) + (m-l)
= 0
So, the correct option is D.
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