Given a and d for the following A.P., find the following A.P.:
a = 3, d = 2
Formula Used.
an = a + (n–1)d
If a = 3, d = 2
Then a1 = a + (n–1)d = 3 + (1–1)2 = 3
a2 = a + (n–1)d = 3 + (2–1)2 = 3 + 2×1 = 5
a3 = a + (n–1)d = 3 + (3–1)2 = 3 + 2×2 = 7
a4 = a + (n–1)d = 3 + (4–1)2 = 3 + 2×3 = 9
an = a + (n–1)d = 3 + (n–1)2 = 2n + 1
∴ The A.P is 3, 5, 7, 9……, 2n + 1
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