How many terms of A.P., 2, 7, 12, 17, ... add up to 990?
Formula used.
Sn =
[2a + (n–1)d]
d = an + 1–an
⇒ S20 = 990
⇒ a = 2
⇒ d = an + 1–an
= 7 – 2 = 5
Sn =
[2×2 + (n–1)5]
990 =
[4 + 5n–5]
990 =
[5n–1]
990×2 = 5n2–n
5n2–n–1980 = 0
n = ![]()
∴ n can be 20 or –19.8
Since, the number of terms cannot be negative
∴ Sum of 20 terms gives the sum of 990
Couldn't generate an explanation.
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