Given a and d for the following A.P., find the following A.P.:
a = 1000, d = –100
Formula Used.
an = a + (n–1)d
If a = 1000, d = –100
Then;
a1 = a + (n–1)d = 1000 + (1–1)(–100) = 1000
a2 = a + (n–1)d = 1000 + (2–1)(–100) = 1000 + (–100)×1 = 900
a3 = a + (n–1)d = 1000 + (3–1)(–100) = 1000 + (–100)×2 = 800
a4 = a + (n–1)d = 1000 + (4–1)(–100) = 1000 + (–100)×3 = 700
an = a + (n–1)d = 1000 + (n–1)(–100) = 1100–100n
∴ The A.P is 1000, 900, 800, 700……, 1100–100n
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