Find the nth term of the following A.P.'s:
50, 100, 150, 200, ...
Formula Used.
dn = an + 1 – an
an = a + (n–1)d
In the above sequence,
a = 50;
d1 = a2–a1 = 100–50 = 50
d2 = a3–a2 = 150–100 = 50
d3 = a4–a3 = 200–150 = 50
The difference in sequence is same and comes to be 50.
∴ The above sequence is A.P
The nth term of A.P is an = a + (n–1)d
an = a + (n–1)d = 50 + (n–1)(50)
= 50 + 50n–50
= 50n
Couldn't generate an explanation.
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