For a given A.P. with
S20 = 100, d = —2, find a.
Formula used.
Sn =
[2a + (n–1)d]
⇒ S20 = 100
⇒ n = 20
⇒ d = –2
S20 =
[2a + (20–1)(–2)]
100 = 10[2a–38]
100 = 20[a–19]
= a–19
5 = a–19
a = 19 + 5
a = 24
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