Skip to content
Philoid
Browse Saved
Back to chapter
Maths
5. Arithmetic Progression
Home · Class 10 · Maths · Ref. Book · 5. Arithmetic Progression
Prev
Next
Q3 of 85 Page 104

For a given A.P. with

S10 = 50, a = 0.5, find d.

Formula used.


Sn = [2a + (n–1)d]


⇒ S10 = 50


⇒ n = 10


⇒ a = 0.5S10 = [2×0.5 + (10–1)d]


50 = 5[1 + 9d]


= 1 + 9d


9d = 10–1


d = = 1


More from this chapter

All 85 →
3

For a given A.P. with

S3 = 9, S7 = 49, find Sn and S10.

3

For a given A.P. with

T10 = 41, S10 = 320, find Tn, Sn.

3

For a given A.P. with

S20 = 100, d = —2, find a.

4

How many terms of A.P., 2, 7, 12, 17, ... add up to 990?

Questions · 85
5. Arithmetic Progression
1 1 1 1 1 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 3 3 4 4 5 5 6 7 8 9 10 11 12 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15
Back to chapter
ADVERTISEMENT
About Contact Privacy Terms
Philoid · 2026
  • Home
  • Search
  • Browse
  • Quiz
  • Saved