For a given A.P. with
S10 = 50, a = 0.5, find d.
Formula used.
Sn =
[2a + (n–1)d]
⇒ S10 = 50
⇒ n = 10
⇒ a = 0.5S10 =
[2×0.5 + (10–1)d]
50 = 5[1 + 9d]
= 1 + 9d
9d = 10–1
d =
= 1
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