Find the sum of the first n terms of the following A.P. as asked for:
1, 1.5, 2, 2.5, 3, ... upto 16 terms
Formula used.
Sn =
[2a + (n–1)d]
d = an + 1–an
In the following A.P
a = 1,
d = a2–a1
= 1.5–1 = 0.5;
n = 16
Sn =
[2a + (n–1)d]
=
[2×1 + (16–1)0.5]
= 8[2 + 15×0.5]
= 8[2 + 7.5]
= 76
Couldn't generate an explanation.
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