Find the sum of the first n terms of the following A.P. as asked for:
2, 6, 10, 14, ... up to 20 terms
Formula used.
Sn =
[2a + (n–1)d]
d = an + 1–an
In the following A.P
a = 2,
d = a2–a1
= 6–2 = 4;
n = 20
Sn =
[2a + (n–1)d]
=
[2×2 + (20–1)4]
= 10[4 + 19×4]
= 10[4 + 76]
= 800
Couldn't generate an explanation.
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