Find the nth term of the following A.P.'s:
2, 7, 12, 17, ...
Formula Used.
dn = an + 1 – an
an = a + (n–1)d
In the above sequence,
a = 2;
d1 = a2–a1 = 7–2 = 5
d2 = a3–a2 = 12–7 = 5
d3 = a4–a3 = 17–12 = 5
The difference in sequence is same and comes to be 5 .
∴ The above sequence is A.P
The nth term of A.P is an = a + (n–1)d
an = a + (n–1)d = 2 + (n–1)(5)
= 2 + 5n–5
= –3 + 5n
Couldn't generate an explanation.
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