If the sum of the three consecutive terms of A.P. is 48 and the product of the first and the last is 252, then d = _____
We know that the sum of 3 nos in the AP is 48.
Lets say that those 3 nos are : a – d, a, a + d
So we can say that, a – d + a + a + d = 48
3a = 48
a= 16
now we have product of the first and the last term out of these 3 to be 252.
Ie. (a – d)(a + d) = 252
⇒ a2 – d2 = 252
we have a = 16, so we put the value of a in the above equation:
⇒ (16)2 – d2 = 252
⇒ 256 – d2 = 252
⇒ d2 = 256 – 252
⇒ d2 = 4
⇒ d=2
∴ the correct option is (a)
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