Q15 of 85 Page 110

If the sum of the three consecutive terms of A.P. is 48 and the product of the first and the last is 252, then d = _____

We know that the sum of 3 nos in the AP is 48.


Lets say that those 3 nos are : a – d, a, a + d


So we can say that, a – d + a + a + d = 48


3a = 48


a= 16


now we have product of the first and the last term out of these 3 to be 252.


Ie. (a – d)(a + d) = 252


a2 – d2 = 252


we have a = 16, so we put the value of a in the above equation:


(16)2 – d2 = 252


256 – d2 = 252


d2 = 256 – 252


d2 = 4


d=2


the correct option is (a)

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