If the first term and the last term of a finite A.P. are 5 and 95 respectively and d = 5, find n and Sn.
Formula used.
an = a + (n–1)d
Sn =
[2a + (n–1)d]
⇒ d = 5
⇒ a = 5
⇒ l = 95
an = a + (n–1)d
95 = 5 + (n–1)5
95 = 5–5 + 5n
n =
= 19
Sn =
[a + l]
=
[5 + 95]
= 19×50
= 950
∴ Number of terms is 19 and Sum of A.P is 950
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