Find the nth term of the following A.P.'s:
200, 195, 190, 185, ...
Formula Used.
dn = an + 1 – an
an = a + (n–1)d
In the above sequence,
a = 200;
d1 = a2–a1 = 195–200 = –5
d2 = a3–a2 = 190–195 = –5
d3 = a4–a3 = 185–190 = –5
The difference in sequence is same and comes to be (–5).
∴ The above sequence is A.P
The nth term of A.P is an = a + (n–1)d
an = a + (n–1)d = 200 + (n–1)(–5)
= 200–5n + 5
= 205–5n
Couldn't generate an explanation.
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