Find the sum of the first n terms of the following A.P. as asked for:
up to 18 terms
Formula used.
Sn =
[2a + (n–1)d]
d = an + 1–an
In the following A.P
a =
,
d = a2–a1
=
= 1;
n = 18
Sn =
[2a + (n–1)d]
=
[2×
+ (18–1)1]
= 9[
+ 17]
= 9[
]
= 159
Couldn't generate an explanation.
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