Q6 of 37 Page 35

Two angles of a triangle are in the ratio 4:5. If the sum of these angles is equal to the third angle. Find the angles.

Let the Triangle be ABC

Given: ∠A = 4x; ∠B = 56x; ∠C = ∠A + ∠B


∠C = 4x + 5x = 9x


From Angle Sum Property


∠A + ∠B + ∠C = 180°


4x + 5x + 9x = 180°


18x = 180°



Hence all the required angles are,


∠A = 4x = 4(10) = 40°


∠B = 5x = 5(10) = 50°


∠C = 9x = 9(10) = 90°


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