Q8 of 37 Page 35

Two years ago father was three times as old as his son two years hence twice his age will be equal to five times that of his son. Find their ages?

Let son's age = x

Two years ago son's age = x – 2.


His Father's age at that time = 3(x – 2).


Present age of Father = 3x – 6 + 2 = 3x – 4


Two years hence father's age = 3x – 4 + 2 = 3x – 2.


Two years hence son's age = x + 2.


According to the question


⇒ 5 × (x + 2) = 2 × (3x – 2)


⇒ 5x + 10 = 6x – 4


⇒ 10 + 4 = 6x – 5x


⇒ 14 = x


Hence,


Son's present age = 14 years.


Father's present age = 38 years.


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