Ritu is four times as old as his brother Raju. In 4 years time her age will be twice of Raju's age. What are their present ages?
Let us assume, the present age of Ritu is x years and the present age of Raju is y years.
Given:
x = 4y ……(i)
Also after 4 years,
⇒ x + 4 = 2 (y + 4)
⇒ x + 4 = 2y + 8
⇒ x – 2y = 4 …… (ii)
Substitute the value of x from equation (i) in equation (ii),
⇒ 4y – 2y = 4
⇒ 2y = 4
⇒ y = 2 years
Therefore, x = 4y = 4 × 2 = 8 years
Hence, the present age of Ritu is 8 years and the age of Raju is 2 years.
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