Find p(0), p(1) and p(2) for each of the following polynomials.
p(x) = x2 - x +1
p(x) = x2 – x + 1
⇒ p(0) = (0)2 – 0 + 1
⇒ p(0) = 1
And,
⇒ p(1) = (1)2 – 1 + 1
⇒ p(1) = 1– 1 + 1
⇒ p(1) = 1
And,
⇒ p(2) = (2)2 – 2 + 1
⇒ p(2) = 4– 2 + 1
⇒ p(2) = 3
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