Q2 of 86 Page 36

Find p(0), p(1) and p(2) for each of the following polynomials.

p(x) = x2 - 3x + 2

p(t) = x2 - 3x + 2


⇒ p(0) = (0)2 – 3(0) + 2


⇒ p(0) = 0– 0 + 2


⇒ p(0) = 2


And,


⇒ p(1) = (1)2 – 3(1) + 2


⇒ p(1) = 1– 3 + 2


⇒ p(0) = 0


And,


⇒ p(2) = (2)2 – 3(2) + 2


⇒ p(2) = 4– 6 + 2


⇒ p(2) = 0


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