Q5 of 86 Page 56

Factorise

25x2 + 16y2 + 4z2 - 40xy + 16yz - 20xz

25x2 + 16y2 + 4z2 - 40xy + 16yz - 20xz


25x2 + 16y2 + 4z2 - 40xy + 16yz - 20xz = 25x2 + 16y2 + 4z2 + (-40xy) + 16yz + (-20xz)


25x2 can be written as (-5x)2


16y2 can be written as (4y)2


4z2 can be written as (2z)2


-40xy can be written as 2(-5x)(4y)


16yz can be written as 2(4y)(2z)


-20xz can be written as 2(-5x)(2z)


25x2 + 16y2 + 4z2 - 40xy + 16yz - 20xz = (-5x)2 + (4y)2 +


(2z)2 + 2(-5x)(4y) + 2(4y)(2z) + 2(-5x)(2z) …(i)


Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca


Comparing (-5x)2 + (4y)2 + (2z)2 + 2(-5x)(4y) + 2(4y)(2z) + 2(-5x)(2z) with a2 + b2 + c2 + 2ab + 2bc + 2ca we get


a = -5x, b = 4y and c = 2z


therefore


(-5x)2 + (4y)2 + (2z)2 + 2(-5x)(4y) + 2(4y)(2z) + 2(-5x)(2z) = (- 5x + 4y + 2z)2


From (i)


25x2 + 16y2 + 4z2 - 40xy + 16yz - 20xz = (- 5x + 4y + 2z)2


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