Factorise the following using appropriate identities.
16x2 + 24xy + 9y2
16x2 can be written as (4x)2
24xy can be written as 2(4x)(3y)
9y2 can be written as (3y)2
⇒ 16x2 + 24xy + 9y2 = (4x)2 + 2(4x)(3y) + (3y)2
Using identity (a + b)2 = a2 + 2ab + b2
Here a = 4x and b = 3y
⇒ 16x2 + 24xy + 9y2 = (4x + 3y)2
Therefore 16x2 + 24xy + 9y2 = (4x + 3y) (4x + 3y)
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