Expand each of the following, using suitable identities
Using identity (a – b)3 = a3 - b3 – 3a2b + 3ab2
Here a = x and b = 
y
⇒ 
= x3 - 
– 3(x)2(
) + 3(x)
⇒ 
= x3 - 
– 2x2y + 
xy2
Therefore 
= x3 - 
– 2x2y + 
xy2
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