Find the remainder when p(x) = x3 – 6x2 + 14x – 3 is divided by g(x) = 1 – 2x and verify the result by long division.
Given: p(x) = x3 – 6x2 + 14x – 3 and g(x) = 1 – 2x
As we know by Remainder Theorem,
If a polynomial p(x) is divided by a linear polynomial (x – a) then, the remainder is p(a)
Therefore, remainder when p(x) is divided by g(x) is ![]()
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∴ the remainder when x3 – 6x2 + 14x – 3 is divided by 1 – 2x is ![]()
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