Expand each of the following, using suitable identities

= [
+
+ 1]2
Using (x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx
Here x =
, y =
and z = 1
⇒
=
+
+ 12 + 2
+ 2
(1) + 2(1)![]()
⇒
=
+
+ 1 +
+ (-b) + ![]()
⇒
=
+
+ 1 -
– b + ![]()
Therefore
=
+
+ 1 -
– b + ![]()
Couldn't generate an explanation.
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