Expand each of the following, using suitable identities
(p + 1)3
Using identity (x + y)3 = x3 + y3 + 3x2y + 3xy2
Here x = p and y = 1
⇒ (p + 1)3 = p3 + 13 + 3(p)2(1) + 3(p)(1)2
= p3 + 13 + 3p2 + 3p
Therefore (p + 1)3 = p3 + 13 + 3p2 + 3p
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