Q3 of 86 Page 36

Verify whether the values of x given in each case are the zeroes of the polynomial or not?

p(x) = (x - 1)(x + 2); x = -1, -2

p(x) = (x - 1)(x + 2)


⇒ p(-1) = (-1 - 1)(-1 + 2);


⇒ p(-1) = -2 × 1


⇒ p(-1) = -2


∴ No x = -1 is not the zero of polynomial (x - 1)(x + 2).


And,


⇒ p(-2) = (-2 - 1)(-2 + 2);


⇒ p(-2) = -3 × 0


⇒ p(-2) = 0


∴ Yes x = -2 is not the zero of polynomial (x - 1)(x + 2).


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