Expand each of the following, using suitable identities
(2a - 3b)3
Using identity (x – y)3 = x3 - y3 – 3x2y + 3xy2
Here x = 2a and y = 3b
⇒ (2a - 3b)3 = (2a)3 – (3b)3 – 3(2a)2(3b) + 3(2a)(3b)2
= 8a3 – 27b3 – 18a2b + 18ab2
Therefore (2a - 3b)3 = 8a3 – 27b3 – 18a2b + 18ab2
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