Find the remainder when 2x2 – 3x + 5 is divided by 2x – 3. Does it exactly divide the polynomial? State reason.
Let p(x) = 2x2 – 3x + 5
As we know by Remainder Theorem,
If a polynomial p(x) is divided by a linear polynomial (x – a) then, the remainder is p(a)
⇒ Remainder of p(x) when divided by 2x – 3 is ![]()
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⇒ Remainder of 2x2 – 3x + 5 when divided by 2x – 3 is ![]()
As on dividing the given polynomial by 2x – 3, we get a non–zero remainder, therefore, 2x – 3 does not complete divide the polynomial.
∴ It is not a factor.
Couldn't generate an explanation.
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