Q2 of 86 Page 36

Find p(0), p(1) and p(2) for each of the following polynomials.

p(y) = 2 + y + 2y2 - y3

p(y) = 2 + y + 2y2 – y3


⇒ p(0) = 2 + 0 + 2(0)2 – (0)3


⇒ p(0) = 2 + 0 + 0– 0


⇒ p(0) = 2


And,


⇒ p(1) = 2 + 1 + 2(1)2 – (1)3


⇒ p(1) = 2 + 1 + 2– 1


⇒ p(1) = 4


And,


⇒ p(2) = 2 + 2 + 2(2)2 – (2)3


⇒ p(2) = 2 + 2 + 8– 8


⇒ p(2) = 4


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