Q2 of 274 Page 52

If find

(i) P(0)


(ii) p(2)


(iii) p(-1)

(i) We have,



Now,


Put y = 0



= 4 - 3(0) - (0) + 5(0)


= 4 – 0 – 0 + 0


= 4


Hence,


P (0) = 4


(ii) We have,



Now,


Put y = 2


2 3


=


=


=


Hence,


P (2) = 46


(iii) We have,



Now,


Put y = -1


2 3


=


=


=


Hence,


p(-1) = -5


More from this chapter

All 274 →
5

Classify the following as linear, quadratic and cubic polynomials:

(i)


(ii)


(iii)


(iv) -7+z


(v) (vi)

1

Iffind

(i) p (0)


(ii)p(3)


(iii) p(-2)

 3

If find

(i) f (0)


(ii) f (4)


(iii) f (-5)

 4

Find the zero of the polynomial:

(i) P(x)=x-5


(ii) q(x)=x+4


(iii) p(t)=2t-3


(iv) f(x)=3x+1


(v) g(x)=5-4x


(vi) h(x)=6x-1


(vii) p(x)=ax + b,a≠0


(viii) q(x) = 4x


(ix) p(x)=ax,a≠0