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2. Polynomials
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Q27 of 274 Page 76

Factorize:

a3 + 3a2b + 3ab2 + b3 – 8

We know that,


(a + b)3 = a3 + b3 + 3ab (a + b)


Using this formula, we get


= (a + b)3 – 8


= (a + b)3 – (2)3


We know that,


a3 - b3 = (a - b) (a2 + a × b + b2)


Using this formula, we get


= (a + b – 2) [(a+ b)2 + 2 (a + b) + 4)]


More from this chapter

All 274 →
25

Factorize:

26

Factorize:

8a3 – b3 – 4ax + 2bx

1

Factorize:

125a3 + b3 + 64c3 – 60abc

2

Factorize:

a3 + 8b3 + 64c3 – 24abc

Questions · 274
2. Polynomials
1 2 3 4 4 4 5 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 1 2 3 4 5 6 1 2 3 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
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